Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Test: Chapter 10 - Page 695: 22


$\sqrt{10600}\approx102.956\text{ }ft$

Work Step by Step

A right triangle is formed with legs $50$ and $90.$ Using $a^2+b^2=c^2$ or the Pythagorean Theorem, then \begin{array}{l}\require{cancel} a^2+b^2=c^2 \\\\ 50^2+90^2=c^2 \\\\ 2500+8100=c^2 \\\\ 10600=c^2 \\\\ c=\sqrt{10600} .\end{array} Hence, the referee jogged $ \sqrt{10600}\approx102.956\text{ }ft .$
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