Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.6 Solving Radical Equations - 10.6 Exercise Set - Page 668: 6

Answer

TRUE

Work Step by Step

Squaring both sides of the given equation, $\sqrt{x}=3,$ gives $(\sqrt{x})^2=3^2.$ Hence the given statement is $\text{ TRUE .}$
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