## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$t=11$
Raising both sides to the $\text{ 4th }$ power, the solution to the given equation, $\sqrt[4]{t+5}=2$, is \begin{array}{l} t+5=16 \\\\ t=16-5 \\\\ t=11 .\end{array} Upon checking, $t=11$ satisfies the given equation.