## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$x=4$
Raising both sides to the $\text{ 2nd }$ power, the solution to the given equation, $\sqrt{7x-3}=5$, is \begin{array}{l} 7x-3=25 \\\\ 7x=25+3 \\\\ 7x=28 \\\\ x=\dfrac{28}{7} \\\\ x=4 .\end{array} Upon checking, $x=4$ satisfies the given equation.