## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 10 - Exponents and Radicals - 10.6 Solving Radical Equations - 10.6 Exercise Set - Page 668: 23

#### Answer

$y=100$

#### Work Step by Step

Using the properties of equality, the given equation, $2y^{1/2}-13=7$, is equivalent to \begin{array}{l} 2y^{1/2}=7+13 \\\\ 2y^{1/2}=20 \\\\ y^{1/2}=\dfrac{20}{2} \\\\ y^{1/2}=10 .\end{array} Raising both sides to the $\text{ 2nd }$ power, the solution to the equation above, $y^{1/2}=10$, is \begin{array}{l} y=100 .\end{array} Upon checking, $y=100$ satisfies the given equation.

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