Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.6 Solving Radical Equations - 10.6 Exercise Set - Page 668: 33



Work Step by Step

Raising both sides to the $\text{ 3rd }$ power, the solution to the given equation, $ (21x+55)^{1/3}=10 $, is \begin{array}{l} 21x+55=1000 \\\\ 21x=1000-55 \\\\ 21x=945 \\\\ x=\dfrac{945}{21} \\\\ x=45 .\end{array}
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