## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$y=-3$
Raising both sides to the $\text{ 4th }$ power, the given equation, $(5y+31)^{1/4}=2$, becomes \begin{array}{l} 5y+31=16 \\\\ 5y=16-31 \\\\ 5y=-15 \\\\ y=-\dfrac{15}{5} \\\\ y=-3 .\end{array} Upon checking, only $y=-3$ satisfies the original equation.