Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.6 Solving Radical Equations - 10.6 Exercise Set - Page 668: 35



Work Step by Step

Using the properties of equality, the given equation, $ \sqrt[3]{3y+6}+7=8 $, is equivalent to \begin{array}{l} \sqrt[3]{3y+6}=8-7 \\\\ \sqrt[3]{3y+6}=1 .\end{array} Raising both sides to the $\text{ 3rd }$ power, the solution to the equation above, $ \sqrt[3]{3y+6}=1 $, is \begin{array}{l} 3y+6=1 \\\\ 3y=1-6 \\\\ 3y=-5 \\\\ y=-\dfrac{5}{3} .\end{array}
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