# Chapter 6 - Factoring, Solving Equations, and Problem Solving - Chapter 6 Review Problem Set - Page 274: 41

{$-\frac{7}{3},\frac{5}{2}$}

#### Work Step by Step

Since the equation is already factored, we need to equate all of the factors to zero in order to solve the equation: $(2x-5)(3x+7)=0$ $(2x-5)=0$ or $(3x+7)=0$ $x=\frac{5}{2}$ or $x=-\frac{7}{3}$ Therefore, the solution set is {$-\frac{7}{3},\frac{5}{2}$}.

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