## Elementary Algebra

{$-\frac{7}{3},\frac{5}{2}$}
Since the equation is already factored, we need to equate all of the factors to zero in order to solve the equation: $(2x-5)(3x+7)=0$ $(2x-5)=0$ or $(3x+7)=0$ $x=\frac{5}{2}$ or $x=-\frac{7}{3}$ Therefore, the solution set is {$-\frac{7}{3},\frac{5}{2}$}.