Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 6 - Factoring, Solving Equations, and Problem Solving - Chapter 6 Review Problem Set - Page 274: 33



Work Step by Step

Using the rules of factoring trinomials to factor the polynomial, we obtain: $x^{2}+3x-28=0$ $x^{2}-4x+7x-28=0$ $x(x-4)+7(x-4)=0$ $(x-4)(x+7)=0$ Now, we equate the two factors to zero and solve: $(x-4)(x+7)=0$ $(x-4)=0$ or $(x+7)=0$ $x=4$ or $x=-7$ Therefore, the solution set is {$-7,4$}.
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