Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 6 - Factoring, Solving Equations, and Problem Solving - Chapter 6 Review Problem Set - Page 274: 38



Work Step by Step

Using the rules of factoring trinomials to factor the polynomial, we obtain: $x^{2}-20x+96=0$ $x^{2}-8x-12x+96=0$ $x(x-8)-12(x-8)=0$ $(x-8)(x-12)=0$ Now, we equate the two factors to zero and solve: $(x-8)(x-12)=0$ $(x-8)=0$ or $(x-12)=0$ $x=8$ or $x=12$ Therefore, the solution set is {$8,12$}.
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