## Elementary Algebra

$\left\{-1, 0, 1\right\}$
Factor out $t$ to obtain: $t(t^2-1)=0$ Factor the difference of two squares using the formula $a^2-b^2=(a-b)(a+b)$ where $a=t$ and $b=1$ to obtain: $t(t-1)(t+1)=0$ Equate each factor to 0 to obtain: $t=0 \text{ or } t-1 = 0 \text{ or } t+1=0$ Solve each equation to obtain: $t=0 \text{ or } t=1 \text{ or } t =-1$ Therefore the solution set is $\left\{-1, 0, 1\right\}$.