Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 6 - Factoring, Solving Equations, and Problem Solving - Chapter 6 Review Problem Set - Page 274: 22



Work Step by Step

Upon inspection, we find that $x$ is common to the first two terms of the expression while $-2$ is common to the last two terms of the expression, so we factor accordingly: $xy-3x-2y+6$ =$x(y-3)-2(y-3)$ Since $(y-3)$ is now common to the expression, we factor it out: $x(y-3)-2(y-3)=(y-3)(x-2)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.