## Elementary Algebra

$(y-3)(x-2)$
Upon inspection, we find that $x$ is common to the first two terms of the expression while $-2$ is common to the last two terms of the expression, so we factor accordingly: $xy-3x-2y+6$ =$x(y-3)-2(y-3)$ Since $(y-3)$ is now common to the expression, we factor it out: $x(y-3)-2(y-3)=(y-3)(x-2)$