Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 6 - Factoring, Solving Equations, and Problem Solving - Chapter 6 Review Problem Set - Page 274: 27



Work Step by Step

Using the rules of factoring trinomials to factor the polynomial, we obtain: $2x^{2}+3x-20=0$ $2x^{2}-5x+8x-20=0$ $x(2x-5)+4(2x-5)=0$ $(2x-5)(x+4)=0$ Now, we equate the two factors to zero and solve: $(2x-5)(x+4)=0$ $(2x-5)=0$ or $(x+4)=0$ $x=\frac{5}{2}$ or $x=-4$ Therefore, the solution set is {$-4,\frac{5}{2}$}.
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