Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 6 - Factoring, Solving Equations, and Problem Solving - Chapter 6 Review Problem Set - Page 274: 39



Work Step by Step

Using the rules of factoring trinomials to factor the polynomial, we obtain: $4t^{2}+17t-15=0$ $4t^{2}-3t+20t-15=0$ $t(4t-3)+5(4t-3)=0$ $(4t-3)(t+5)=0$ Now, we equate the two factors to zero and solve: $(4t-3)(t+5)=0$ $(4t-3)=0$ or $(t+5)=0$ $t=\frac{3}{4}$ or $t=-5$ Therefore, the solution set is {$-5,\frac{3}{4}$}.
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