#### Answer

{$-2,3$}

#### Work Step by Step

Since $(x+2)$ is common to both the terms of the equation, we take it out as a common factor:
$3(x+2)-x(x+2)=0$
$(x+2)(3-x)=0$
Now, we equate all the factors to zero to solve the equation:
$(x+2)(3-x)=0$
$x+2=0$ or $3-x=0$
$x=-2$ or $x=3$
Therefore, the solution set is {$-2,3$}.