Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.6 - Integral Exponents and Scientific Notation - Problem Set 5.6: 75

Answer

$a^{4}b^{8}$

Work Step by Step

Using the laws of exponents, the given expression, $ \left( \dfrac{a^{-1}}{b^{2}} \right)^{-4} ,$ is equivalent to \begin{array}{l}\require{cancel} \dfrac{a^{-1(-4)}}{b^{2(-4)}} \\\\= \dfrac{a^{4}}{b^{-8}} \\\\= a^{4}b^{8} .\end{array}
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