Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.6 - Integral Exponents and Scientific Notation - Problem Set 5.6: 68

Answer

$\dfrac{25}{a^2}$

Work Step by Step

Using the laws of exponents, the given expression, $ (5a^{-1})^{2} ,$ is equivalent to \begin{array}{l}\require{cancel} 5^2a^{-1(2)} \\\\= 25a^{-2} \\\\= \dfrac{25}{a^2} .\end{array}
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