Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.6 - Integral Exponents and Scientific Notation - Problem Set 5.6 - Page 224: 88

Answer

2 $\times$ $10^{-7}$

Work Step by Step

We need to write 0.0000002 as the product of a number greater than or equal to 1 and less than 10, and an integral power of 10. The number greater than or equal to 1 and less than 10 will be 2. The decimal point has moved 7 places to the left, so the exponent of 10 will be -7. So, 0.0000002 = 2 $\times$ $10^{-7}$
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