Answer
$\dfrac{x^2y}{2}$
Work Step by Step
Using the laws of exponents, the given expression, $
(2x^{-2}y^{-1})^{-1}
,$ is equivalent to
\begin{array}{l}\require{cancel}
2^{-1}x^{-2(-1)}y^{-1(-1)}
\\\\=
2^{-1}x^{2}y^{1}
\\\\=
\dfrac{x^2y}{2^1}
\\\\=
\dfrac{x^2y}{2}
.\end{array}
