Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.6 - Integral Exponents and Scientific Notation - Problem Set 5.6: 79

Answer

$x$

Work Step by Step

Using the laws of exponents, the given expression, $ \left( \dfrac{x^{2}}{x^{3}} \right)^{-1} ,$ simplifies to \begin{array}{l}\require{cancel} \left( x^{2-3} \right)^{-1} \\\\= \left( x^{-1} \right)^{-1} \\\\= x^{-1(-1)} \\\\= x^{1} \\\\= x .\end{array}
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