Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.6 - Integral Exponents and Scientific Notation - Problem Set 5.6: 76

Answer

$\dfrac{1}{a^{9}b^{6}}$

Work Step by Step

Using the laws of exponents, the given expression, $ \left( \dfrac{a^{3}}{b^{-2}} \right)^{-3} ,$ is equivalent to \begin{array}{l}\require{cancel} \dfrac{a^{3(-3)}}{b^{-2(-3)}} \\\\= \dfrac{a^{-9}}{b^{6}} \\\\= \dfrac{1}{a^{9}b^{6}} .\end{array}
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