Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.6 - Integral Exponents and Scientific Notation - Problem Set 5.6: 112

Answer

$40,000$

Work Step by Step

(i) Scientific notation has the form $a(10^n)$, where $1 \le a \lt 10$ and where $n$ is an integer. (ii) $\frac{a^{m}}{a^{n}}=a^{m-n}$ Write each number in scientific notation to obtain: $=\dfrac{4.8(10^{2})}{1.2(10^{-2})}$ Divide $4.8$ and $1.2$ together and the powers of 10 together to obtain: $=\dfrac{4.8}{1.2} \cdot \dfrac{10^2}{10^{-2}} \\=4 \cdot 10^{2-(-2)} \\=4 \cdot 10^{2+2} \\=4(10^4) \\=40,000$
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