## Elementary Algebra

$\dfrac{9b}{22a}$
Cancelling the common factor in the numerator and the denominator, the given expression, $\dfrac{9a^3b^3}{22a^4b^2} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{a^3b^2}\cdot9b}{\cancel{a^3b^2}\cdot22a} \\\\= \dfrac{9b}{22a} .\end{array}