## Elementary Algebra

$\dfrac{3x^2}{2y^3}$
Cancelling the common factor in the numerator and the denominator, the given expression, $\dfrac{18x^3y}{12xy^4} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{6xy}\cdot3x^2}{\cancel{6xy}\cdot2y^3} \\\\= \dfrac{3x^2}{2y^3} .\end{array}