Answer
$\dfrac{11}{3y}$
Work Step by Step
Cancelling the common factor in the numerator and the denominator, the given expression, $
\dfrac{22xy^2}{6xy^3}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{\cancel{2xy^2}\cdot11}{\cancel{2xy^2}\cdot3y}
\\\\=
\dfrac{11}{3y}
.\end{array}
