## Elementary Algebra

$\dfrac{11}{3y}$
Cancelling the common factor in the numerator and the denominator, the given expression, $\dfrac{22xy^2}{6xy^3} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{2xy^2}\cdot11}{\cancel{2xy^2}\cdot3y} \\\\= \dfrac{11}{3y} .\end{array}