## Elementary Algebra

$\dfrac{4xy}{7}$
Cancelling the common factor in the numerator and the denominator, the given expression, $\dfrac{8x^2y}{14x} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{2x}\cdot4xy}{\cancel{2x}\cdot7} \\\\= \dfrac{4xy}{7} .\end{array}