# Chapter 2 - Real Numbers - 2.4 - Exponents - Problem Set 2.4 - Page 75: 66

$\dfrac{4xy}{7}$

#### Work Step by Step

Cancelling the common factor in the numerator and the denominator, the given expression, $\dfrac{8x^2y}{14x} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{2x}\cdot4xy}{\cancel{2x}\cdot7} \\\\= \dfrac{4xy}{7} .\end{array}

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