Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.4 - Exponents - Problem Set 2.4: 51

Answer

$8a^5$

Work Step by Step

Simplify by multiplying the coefficients together. Also, recall that $a^{b}a^{c}=a^{b+c}$. Thus, we obtain: $=[-4\cdot (-2)](a^2\cdot a^3) \\=8a^{2+3} \\=8a^5$
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