## Elementary Algebra

Published by Cengage Learning

# Chapter 2 - Real Numbers - 2.4 - Exponents - Problem Set 2.4 - Page 75: 69

#### Answer

$\dfrac{7b^2}{17a}$

#### Work Step by Step

Cancelling the common factor in the numerator and the denominator, the given expression, $\dfrac{7a^2b^3}{17a^3b} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{a^2b}\cdot7b^2}{\cancel{a^2b}\cdot17a} \\\\= \dfrac{7b^2}{17a} .\end{array}

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