Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.4 - Exponents - Problem Set 2.4: 65

Answer

$\dfrac{3y}{5}$

Work Step by Step

Cancelling the common factor in the numerator and the denominator, the given expression, $ \dfrac{9xy}{15x} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{3x}\cdot3y}{\cancel{3x}\cdot5} \\\\= \dfrac{3y}{5} .\end{array}
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