## Elementary Algebra

$\dfrac{3y}{5}$
Cancelling the common factor in the numerator and the denominator, the given expression, $\dfrac{9xy}{15x} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{3x}\cdot3y}{\cancel{3x}\cdot5} \\\\= \dfrac{3y}{5} .\end{array}