## Elementary Algebra

Published by Cengage Learning

# Chapter 2 - Real Numbers - 2.1 - Rational Numbers: Multiplication and Division - Problem Set 2.1 - Page 48: 63

#### Answer

($\frac{3x}{4y}$) $\times$ ($\frac{8}{9x}$) $\times$ ($\frac{12y}{5}$) =$\frac{8}{5}$

#### Work Step by Step

($\frac{3x}{4y}$) $\times$ ($\frac{8}{9x}$) $\times$ ($\frac{12y}{5}$) = Multiply the numerators by each other, and multiply the denominators by each other $\frac{3x\ \times\ 8\ \times\ 12y}{4y\ \times\ 9x\ \times\ 5}$ = Factor the numerator and the denominator $\frac{3\ \times\ x\ \times\ 2\ \times\ 2\ \times\ 2\ \times\ 2\ \times\ 2\ \times\ 3\ \times\ y}{2\ \times\ 2\ \times\ y\ \times\ 3\ \times\ 3\ \times\ x\ \times\ 5}$ = Cancel the common factors between the numerator and the denominator to obtain: $\frac{2\ \times\ 2\ \times\ 2\ }{5}$ = $\frac{8}{5}$

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