Answer
($\frac{3x}{4y}$) $\times$ ($\frac{8}{9x}$) $\times$ ($\frac{12y}{5}$) =$\frac{8}{5}$
Work Step by Step
($\frac{3x}{4y}$) $\times$ ($\frac{8}{9x}$) $\times$ ($\frac{12y}{5}$) =
Multiply the numerators by each other, and multiply the denominators by each other
$\frac{3x\ \times\ 8\ \times\ 12y}{4y\ \times\ 9x\ \times\ 5}$ =
Factor the numerator and the denominator
$\frac{3\ \times\ x\ \times\ 2\ \times\ 2\ \times\ 2\ \times\ 2\ \times\ 2\ \times\ 3\ \times\ y}{2\ \times\ 2\ \times\ y\ \times\ 3\ \times\ 3\ \times\ x\ \times\ 5}$ =
Cancel the common factors between the numerator and the denominator to obtain:
$\frac{2\ \times\ 2\ \times\ 2\ }{5}$ =
$\frac{8}{5}$
