## Elementary Algebra

$\dfrac{2}{3}$
RECALL: $\dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b} \times \dfrac{d}{c}$ Use the rule above to obtain: $=\dfrac{-34}{n} \times \dfrac{n}{-51} \\=\dfrac{-17(2)}{n} \times \dfrac{n}{-17(3)}$ Cancel common factors then multiply to have: $\require{cancel} \\=\dfrac{\cancel{-17}(2)}{\cancel{n}} \times \dfrac{\cancel{n}}{\cancel{-17}(3)} \\=\dfrac{2}{3}$