Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.1 - Rational Numbers: Multiplication and Division - Problem Set 2.1: 19

Answer

$-\dfrac{5a}{13c}$

Work Step by Step

Cancelling the common factor between the numerator and the denominator, the given expression, $ \dfrac{-20ab}{52bc} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{4b}\cdot(-5a)}{\cancel{4b}\cdot13c} \\\\= \dfrac{-5a}{13c} \\\\= -\dfrac{5a}{13c} \end{array}
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