## Elementary Algebra

$-\dfrac{5a}{13c}$
Cancelling the common factor between the numerator and the denominator, the given expression, $\dfrac{-20ab}{52bc} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{4b}\cdot(-5a)}{\cancel{4b}\cdot13c} \\\\= \dfrac{-5a}{13c} \\\\= -\dfrac{5a}{13c} \end{array}