Elementary Algebra

$\dfrac{24}{77}$
First, cancel out the common factors to obtain: $\require{cancel} \\=\dfrac{4\cancel{a}}{11\cancel{b}} \cdot \dfrac{6\cancel{b}}{7\cancel{a}} \\=\dfrac{4}{11} \cdot \dfrac{6}{7}$ Multiply the numerators by each other and the denominators by each other to obtain: $=\dfrac{24}{77}$