## Elementary Algebra

$\dfrac{4x}{5}$
Cancelling the common factor between the numerator and the denominator, the given expression, $\dfrac{68xyz}{85yz} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{17yz}\cdot4x}{\cancel{17yz}\cdot5} \\\\= \dfrac{4x}{5} \end{array}