Answer
$\dfrac{7z}{12x}$
Work Step by Step
First, factor each expression to obtain:
$=\dfrac{5y}{2(4x)} \cdot \dfrac{2(7z)}{5y(3)}$
Cancel the common factors to obtain:
$\require{cancel}
=\dfrac{\cancel{5y}}{\cancel{2}(4x)} \cdot \dfrac{\cancel{2}(7z)}{\cancel{5y}(3)}
\\=\dfrac{1}{4x} \cdot \dfrac{7z}{3}$
Multiply the numerators together and the denominators together to obtain:
$=\dfrac{7z}{12x}$
