## Elementary Algebra

$\dfrac{7z}{12x}$
First, factor each expression to obtain: $=\dfrac{5y}{2(4x)} \cdot \dfrac{2(7z)}{5y(3)}$ Cancel the common factors to obtain: $\require{cancel} =\dfrac{\cancel{5y}}{\cancel{2}(4x)} \cdot \dfrac{\cancel{2}(7z)}{\cancel{5y}(3)} \\=\dfrac{1}{4x} \cdot \dfrac{7z}{3}$ Multiply the numerators together and the denominators together to obtain: $=\dfrac{7z}{12x}$