## Elementary Algebra

$-\dfrac{2xw}{3yz}$
First, cancel common factors to obtain: $\require{cancel} \\=\dfrac{\cancel{3}x}{\cancel{4}y} \cdot \dfrac{-\cancel{8}2w}{\cancel{9z}3} \\=\dfrac{x}{y} \cdot \dfrac{-2w}{3z}$ Multiply the numerators together and the denominators together to obtain: $=\dfrac{-2xw}{3yz} \\=-\dfrac{2xw}{3yz}$