## Elementary Algebra

$-1$
RECALL: $\dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b} \cdot \dfrac{d}{c}$ Use the rule above to obtain: $\\=\dfrac{7}{8} \cdot \dfrac{-16}{14}$ Factor, and then cancel the common factors to obtain: $\require{cancel} \\=\dfrac{7}{8} \cdot \dfrac{-2 \cdot 8}{7 \cdot 2} \\=\dfrac{\cancel{7}}{\cancel{8}} \cdot \dfrac{-\cancel{2} \cdot \cancel{8}}{\cancel{7} \cdot \cancel{2}} \\=-1$