## Elementary Algebra

Published by Cengage Learning

# Chapter 10 - Quadratic Equations - Chapter 10 Test - Page 469: 8

#### Answer

$x = \frac{3±\sqrt {29}}{2}$

#### Work Step by Step

This equation is not easily factorable, so we use the quadratic formula, where the current equation is in the form $0=ax^{2}+bx+c$ $x^{2} -3x - 5 = 0$ $x = \frac{-b±\sqrt {b^{2}-4ac}}{2a}$ $x = \frac{-(-3)±\sqrt {(-3)^{2}-4(1)(-5)}}{2(1)}$ $x = \frac{3±\sqrt {9+20}}{2}$ $x = \frac{3±\sqrt {29}}{2}$

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