Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - Chapter 10 Test: 11

Answer

{$-12,2$}

Work Step by Step

Using the rules for factoring trinomials, we obtain: $y^{2}+10y=24$ $y^{2}+10y-24=0$ $y^{2}-2y+12y-24=0$ $y(y-2)+12(y-2)=0$ $(y-2)(y+12)=0$ $(y-2)=0$ or $(y+12)=0$ $y=2$ or $y=-12$ Therefore, the solution set is {$-12,2$}.
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