Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - Chapter 10 Test - Page 469: 7



Work Step by Step

Using the rules for factoring trinomials, we obtain: $8x^{2}-10x+3=0$ $8x^{2}-4x-6x+3=0$ $4x(2x-1)-3(2x-1)=0$ $(2x-1)(4x-3)=0$ $(2x-1)=0$ or $(4x-3)=0$ $2x=1$ or $4x=3$ $x=\frac{1}{2}$ or $x=\frac{3}{4}$ Therefore, the solution set is {$\frac{1}{2},\frac{3}{4}$}.
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