Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - Chapter 10 Test - Page 469: 6



Work Step by Step

Simplifying the expression through division and then applying square root on both sides, we obtain: $4x^{2}=64$ $x^{2}=\frac{64}{4}$ $x^{2}=16$ $\sqrt {x^{2}}=\pm\sqrt {16}$ $\sqrt {x^{2}}=\pm\sqrt {4^{2}}$ $x=\pm 4$ Therefore, the solution set is {$-4,4$}.
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