## Elementary Algebra

Published by Cengage Learning

# Chapter 10 - Quadratic Equations - Chapter 10 Test - Page 469: 21

No solution

#### Work Step by Step

1. Use the quadratic formula to solve for $n$, where the quadratic equation is in the form $an^{2}+bn+c$. $n^{2} -5n + 7 = 0$ $n = \frac{-b±\sqrt {b^{2}-4ac}}{2a}$ $n = \frac{-(-5)±\sqrt {(-5)^{2}-4(1)(7)}}{2(1)}$ $n = \frac{5±\sqrt {25-28}}{2}$ Square roots cannot be negative. Thus, because $\sqrt{25-28}=\sqrt{-3}$, there is no solution to this equation.

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