Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - Chapter 10 Test - Page 469: 5



Work Step by Step

Using Property 10.1, which says that for any non-negative real number $a$, $x^{2}=a$ can be written as $x=\pm\sqrt a$, we obtain: Step 1: $(3x+2)^{2}=49$ Step 2: $3x+2=\pm \sqrt {49}$ Step 3: $3x+2=\pm 7$ Step 4: $3x+2=7$ or $3x+2=-7$ Step 5: $3x=7-2$ or $3x=-7-2$ Step 6: $3x=5$ or $3x=-9$ Step 7: $x=\frac{5}{3}$ or $x=-3$ The solution set is {$-3,\frac{5}{3}$}.
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