Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - Chapter 10 Test: 12

Answer

$x = \frac{3±\sqrt {41}}{4}$

Work Step by Step

This equation is not easily factorable, so we use the quadratic formula, where the current equation is in the form $0=ax^{2}+bx+c$. Thus, we obtain: $2x^{2} - 3x - 4 = 0$ $x = \frac{-b±\sqrt {b^{2}-4ac}}{2a}$ $x = \frac{-(-3)±\sqrt {(-3)^{2}-4(2)(-4)}}{2(2)}$ $x = \frac{3±\sqrt {9+32}}{4}$ $x = \frac{3±\sqrt {41}}{4}$
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