Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 10 - Quadratic Equations - Chapter 10 Test: 16

Answer

$n = 13, 15$

Work Step by Step

1. Use the distributive property: $n(n-28) = -195$ $n^{2}-28n=-195$ 2. Set the equation equal to zero: $n^{2} - 28n + 195 = 0$ 3. Find two numbers that can be multiplied together to obtain $195$ and can be added together to obtain $-28$: $-13$ and $-15$ $(n-13)(n-15) = 0$ $n - 13 = 0$ $n = 13$ $n - 15 = 0$ $n = 15$ $n = 13, 15$
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