Answer
See below
Work Step by Step
Given $F(x)=4x\sin x-3e^{-2x}$
Since, $(D^2+1)^2$ is the annihilator of $G(x)=3e^{-2x}$
Also, we have: $(D+2)$ is the annihilator of $H(x)=4x\sin x$.This implies that the $(D+2)$ is the annihilator of $4H(x)=4x\sin x$
So, $F(x)=4H(x)-G(x)$
Therefore, $(D+2)(D^2+1)^2$ is the annihilator of F(x).