Answer
100
Work Step by Step
$$C(n,r) = \frac{n!}{r!*(n-r)!}$$
Since $n-r_1 = r_2$ and $n-r_2 = r_1$, Thus $5_{C_2} = 5_{C_3}$
$$\frac{(5!)^2}{(3!)^2(2!)^2}$$This equals 100.
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