College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Chapter 8 Review - Exercises - Page 641: 66

Answer

a) $\$482.77$ b) $\$608.56$

Work Step by Step

a) The loan must be repaid with regular payments $R$, so the payments from an annuity whose present value $A_p$ represents the amount of the loan. We are given: $$\begin{cases} A_p=60,000\\ n=12\cdot 30=360\\ i=\dfrac{0.09}{12}=0.0075. \end{cases}$$ We will use the formula: $$R=\dfrac{iA_p}{1-(1+i)^{-n}},$$ with $Ap=60,000$, $i=0.0075$ and $n=360$: $$R=\dfrac{0.0075(60000)}{1-(1+0.0075)^{-360}}\approx 482.77.$$ b) We are given: $$\begin{cases} A_p=60,000\\ n=12\cdot 15=180\\ i=\dfrac{0.09}{12}=0.0075. \end{cases}$$ We will use the formula: $$R=\dfrac{iA_p}{1-(1+i)^{-n}},$$ with $Ap=60,000$, $i=0.0075$ and $n=180$: $$R=\dfrac{0.0075(60000)}{1-(1+0.0075)^{-180}}\approx 608.56.$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.