College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Chapter 8 Review - Exercises - Page 641: 60

Answer

$\frac{a}{1-b^2} $

Work Step by Step

Since $|b|\lt 1$ so is $b^2$ Thus the sum is $\frac{a}{1-b^2} $
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